Codechef Problems: Cloud Watching (CWCTH)

 Problem Statement: 

https://www.codechef.com/problems/CWCTH

Solution: 

Given, 

    A : number of clouds in morning 

    B : number of clouds in evening 

condition: rain if A is at least three times B otherwise it will be dry 

so solution 

condition 1: if A >= 3 * B

output: Rain 

condition 2: otherwise 

output: Dry 

Code Solution: 

#include <bits/stdc++.h>

using namespace std;

int main() {

    int a, b;

    cin >> a >> b;

    if (b >= 3 * a) {

        cout << "Rain" << endl;

    } else {

        cout << "Dry" << endl;

    }

    return 0;

}