Codechef Problems: CodeMat (CDMT)
Problem Statement:
Solution:
Given,
X : number of participant in past event
Y : Present number of participants
to find, Determine whether this year's event is more successful
Code Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
int x, y;
cin >> x >> y;
if (x > y)
cout << "no";
else
cout << "yes";
}
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