Codechef Problems: Popcorn Buying (POPCORN7)

 Problem Statement:

https://www.codechef.com/problems/POPCORN7

Solution: 

Given X: be the amount of money chef has (X >= 100)

part 1: Deduction of ticket money (ticket price : 50rs)

Y: Remaining Money 

Y = X - 100 

part 2: No of popcorn baskets he can buy 

Integer value of  (Y/50) because each popcorn basket costs 50rs. 

Code Solution: 

#include <bits/stdc++.h>

using namespace std;

int main() {

    int x; 

    cin >> x; 

    

    int y = (x - 100) / 50; 

    cout << y << endl; 

    return 0; 

}