Codechef Problems: Triangles (TRIANGLE7)

 Problem Statement: 

It is well known fact in mathematics that the sum of the $3$ angles in a triangle is $180$ degrees.

You had a triangle, but unfortunately you only remember the $1^{st}$ and $2^{nd}$ angles of it, and you have forgotten the $3^{rd}$ one.

Given that the first angle was $A$, and the second was $B$, can you figure out the third one? All angles are integers measured in degrees.

Input Format

• The first and only line of input contains $2$ integers - $A$ and $B$.

Output Format

Print a single integer - the measure of the $3^{rd}$ angle (in degrees).

Constraints

• $1\le A,B<180$
• $A+B<180$

Solution: 

Given, 

    A : First Angle of Triangle 

    B : Second Angle of Triangle 

To find, 

    C : Third angle of Triangle 

By Angle Sum property of Triangle, 

    A + B + C = 180'

    C = 180 - (A + B)

Code Solution: 

#include <bits/stdc++.h>

using namespace std;

int main() {

    int a, b;

    cin >> a >> b;

    cout << 180 - (a + b) << endl;

    return 0;

}